The product of any three consecutive natural numbers is always divisible by · ABC26GN0299

Let the required product be n (n + 1) (n + 2). Then, n = 1 ⇒ n (n + 1) (n + 2) = (1 × 2 × 3) = 6. n = 2 ⇒ n (n + 1) (n + 2) = (2 × 3 × 4) = 24. n = 3 ⇒ n (n + 1) (n + 2) = (3 × 4 × 5) = 60. So, each such product is divisible by 6.