Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
The greatest number by which the product of three consecutive multiples of 3 is always divisible is
(a)54
(b)81
(c)162
(d)243
Answer
Answer (as printed): C
Explanation
Three consecutive multiples of 3 are 3m, 3(m + 1) and 3(m + 2). Their product = 3m × 3(m + 1) × 3(m + 2) = 27 × m × (m + 1) × (m + 2). Putting m = 1, this product is (27 × 1 × 2 × 3) = 162. So, this product is always divisible by 162.
Explanation as extracted from the printed page; notation may be imperfect.