What least number must be added to 1056 to get a number exactly divisible by 23? · ABC26GN0316

Subject: General Aptitude · Chapter: Number System · Exam: P.C.S. 2009

What least number must be added to 1056 to get a number exactly divisible by 23?

(a)2

(b)3

(c)21

(d)25

Answer

Answer (as printed): A

Explanation

On dividing 1056 by 23, we get 21 as remainder. $\therefore$ Required number to be added $=(23-21)=2$.

Explanation as extracted from the printed page; notation may be imperfect.

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