On dividing a number by 19, the difference between quotient and remainder is 9. The number is · ABC26GN0339

Since the required number is a 3-digit number, so on dividing by 19, it would yield a two-digit quotient which means that the quotient is greater than the remainder. Let the remainder be $x$. Then, quotient $=x+9$. So, number $N=19(x+9)+x=20 x+171$. $\therefore(N-171)$ must be divisible by 20. Clearly, $(371-171)=200$, which is divisible by 20 . Hence, the required number = 371.