In a division sum, the remainder was 71. With the same divisor but twice the dividend, the remainder is 43… · ABC26GN0350
Subject: General Aptitude · Chapter: Number System
In a division sum, the remainder was 71. With the same divisor but twice the dividend, the remainder is 43. Which one of the following is the divisor?
(a)86
(b)93
(c)99
(d)104
Answer
Answer (as printed): C
Explanation
Let the dividend be $(x+71)$ and the divisor be $y$. Then, $[2(x+71)-43]$ is divisible by $y \Rightarrow(2 x+142-43)$ is divisible by $y$ $\Rightarrow(2 x+99)$ is divisible by $y$. ∴ Divisor $=99$ Shortcut Method: Divisor $=(2 \times 71-43)=(142-43)=99$.
Explanation as extracted from the printed page; notation may be imperfect.