A number when divided by three consecutive numbers 9, 11, 13 leaves the remainders 8, 9 and 8 respectively… · ABC26GN0355

Subject: General Aptitude · Chapter: Number System · Exam: R.R.B. 2008

A number when divided by three consecutive numbers 9, 11, 13 leaves the remainders 8, 9 and 8 respectively. If the order of divisors is reversed, the remainders will be

(a)10, 8, 9

(b)10, 1, 6

(c)8, 9, 8

(d)9, 8, 8

Answer

Answer (as printed): B

Explanation

9 | $x$ ; 11 | $y-8$ ; 13 | $z-9$ ; 1-8 $$\begin{aligned} & z=13 \times 1+8=21 \\ & y=11 \times z+9=11 \times 21+9=240 \\ & x=9 \times y+8=9 \times 240+8=2168 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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