ABC26GN0357 · Number System
Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
A number is successively divided by 8, 7 and 3 giving residues 3, 4 and 2 respectively and quotient 31. The number is
(a)3555
(b)5355
(c)5535
(d)5553
Answer
Explanation
8 | $x$ ; 7 | $y-3$ ; 3 | $z-4$ ; 31-2 $$\begin{aligned} & z=3 \times 31+2=95 \\ & y=7 \times z+4=7 \times 95+4=669 \\ & x=8 \times y+3=8 \times 669+3=5355 \end{aligned}$$ ∴ Required number $=5355$.
Explanation as extracted from the printed page; notation may be imperfect.
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