Subject: General Aptitude · Chapter: Number System · Exam: · Marks: · Difficulty:
If (the place value of 5 in 15201) + (the place value of 6 in 2659) $=7 \times$ $\_\_\_\_$ , then the number of the blank space is:
(a)800
(b)80
(c)90
(d)900 [CTET, 2016]
Answer
Answer (as printed): A
Explanation
The place value of 5 in 15201 = 5000 Place value of 6 in $2659=600$ $$\therefore \quad \begin{aligned} \text { we have } 5000+600 & =7 x \\ 7 x & =5600 \\ x=\frac{5600}{7} & =800 \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.