ABC26GN0453 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:

$\frac{1095}{1168}$ when expressed in simplest form is

(a)$\frac{13}{16}$

(b)$\frac{15}{16}$

(c)$\frac{17}{26}$

(d)$\frac{25}{26}$

Answer

Answer (as printed): B

Explanation

So, H.C.F. of 1095 and 1168 = 73. ∴ $\frac{1095}{1168} = \frac{1095 \div 73}{1168 \div 73} = \frac{15}{16}$.

Explanation as extracted from the printed page; notation may be imperfect.