Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is
(a)101
(b)107
(c)111
(d)185
Answer
Answer (as printed): C
Explanation
Let the numbers be 37a and 37b. Then, $37 a \times 37 b=4107 \Rightarrow a b=3$. Now, co-primes with product 3 are (1, 3). So, the required numbers are (37 × 1, 37 × 3) i.e., (1, 111). $\therefore \quad$ Greater number = 111.
Explanation as extracted from the printed page; notation may be imperfect.