Product of numbers $=29 \times 4147$. Let the numbers be $29 a$ and $29 b$. Then, $29 a \times 29 b=(29 \times 4147) \Rightarrow a b=143$. Now, co-primes with product 143 are (1, 143) and (11, 13). So, the numbers are $(29 \times 1,29 \times 143)$ and $(29 \times 11,29 \times 13)$. Since both numbers are greater than 29, the suitable pair is ( $29 \times 11,29 \times 13$ ), i.e., (319, 377). $$\therefore \quad \text { Required sum }=(319+377)=696 .$$
Explanation as extracted from the printed page; notation may be imperfect.