ABC26GN0521 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: 2007 · Marks: · Difficulty:

A person has to completely put each of three liquids: 403 litres of petrol, 465 litres of diesel and 496 litres of Mobil Oil in bottles of equal size without mixing any of the above three types of liquids such that each bottle is completely filled. What is the least possible number of bottles required?
(a)34
(b)44
(c)46
(d)None of these
Answer
Answer (as printed): B
Explanation
For the least number of bottles, the capacity of each bottle must be maximum. $\therefore$ Capacity of each bottle = H.C.F. of 403 litres, 465 litres and 496 litres = 31 litres. Hence, required number of bottles $$=\left(\frac{403+465+496}{31}\right)=\frac{1364}{31}=44 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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