ABC26GN0546 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: · Marks: · Difficulty:

The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is

(a)1008

(b)1015

(c)1022

(d)1032

Answer

Answer (as printed): B

Explanation

Required number = (L.C.M. of 12, 16, 18, 21, 28) + 7 $$\text { = } 1008+7=1015 .$$

Explanation as extracted from the printed page; notation may be imperfect.