Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: 2007 · Marks: · Difficulty:
The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is
(a)1677
(b)1683
(c)2523
(d)3363
Answer
Answer (as printed): B
Explanation
L.C.M. of 5, 6, 7, $8=840$. ∴ Required number is of the form $840 k+3$. Least value of $k$ for which $(840 k+3)$ is divisible by 9 is $k=2$. $\therefore \quad$ Required number $=(840 \times 2+3)=1683$.
Explanation as extracted from the printed page; notation may be imperfect.