ABC26GN0562 · H.C.F. and L.C.M. of Numbers

Subject: General Aptitude · Chapter: H.C.F. and L.C.M. of Numbers · Exam: 2008 · Marks: · Difficulty:

When Seeta made necklaces of either 16 beads, 20 beads or 36 beads, not a single bead was left over. What could be the least number of beads Seeta had?
(a)700
(b)720
(c)750
(d)780
Answer
Answer (as printed): B
Explanation
Required number of beads = L.C.M. of 16, 20, $36=720$.

Explanation as extracted from the printed page; notation may be imperfect.

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