Find the value of (1.99)². · ABC26GN0600

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: Campus Recruitment 2009

Find the value of $(1.99)^{2}$.

Answer

No answer key was printed for this question.

Explanation

$(1.99)^{2} = (2-0.01)^{2} = 2^{2}+(0.01)^{2}-2\times2\times0.01 = 4+0.0001-0.04 = 3.9601$.

Explanation as extracted from the printed page; notation may be imperfect.

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