ABC26GN0665 · Decimal Fractions

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: · Marks: · Difficulty:

(. 00625 of $\frac{23}{5}$ ) when expressed as a vulgar fraction, equals
(a)$\frac{23}{80}$
(b)$\frac{23}{800}$
(c)$\frac{23}{8000}$
(d)$\frac{125}{23}$
Answer
Answer (as printed): B
Explanation
$\left(.00625\right.$ of $\left.\frac{23}{5}\right)=\left(\frac{625}{100000} \times \frac{23}{5}\right)=\frac{23}{800}$.

Explanation as extracted from the printed page; notation may be imperfect.

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