ABC26GN0773 · Decimal Fractions

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: 2005 · Marks: · Difficulty:

The value of $(.98)^{3}+(.02)^{3}+3 \times .98 \times .02-1$ is
(a)0
(b)1
(c)1.09
(d)1.98
Answer
Answer (as printed): A
Explanation
Given expression $=\left[(.98)^{3}+(.02)^{3}+3 \times .98 \times .02\right.$ $$(.98+.02)]-1=(.98+.02)^{3}-1=(1)^{3}-1=0 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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