The value of ((2.697-0.498)²+(2.697+0.498)²)/(2.697 × 2.697+0.498 × 0.498) is · ABC26GN0775

Subject: General Aptitude · Chapter: Decimal Fractions

The value of $\frac{(2.697-0.498)^{2}+(2.697+0.498)^{2}}{2.697 \times 2.697+0.498 \times 0.498}$ is

(a)0.5

(b)2

(c)2.199

(d)3.195

Answer

Answer (as printed): B

Explanation

Given expression $=\frac{(a-b)^{2}+(a+b)^{2}}{a^{2}+b^{2}}=\frac{2\left(a^{2}+b^{2}\right)}{\left(a^{2}+b^{2}\right)}=2$.

Explanation as extracted from the printed page; notation may be imperfect.

Study loop for Decimal Fractions