The value of (2.697-0.498)2+(2.697+0.498)22.697 2.697+0.498 0.498 is

ABC26GN0775 · Decimal Fractions

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: · Marks: · Difficulty:

The value of $\frac{(2.697-0.498)^{2}+(2.697+0.498)^{2}}{2.697 \times 2.697+0.498 \times 0.498}$ is

(a)0.5

(b)2

(c)2.199

(d)3.195

Answer

Answer (as printed): B

Explanation

Given expression $=\frac{(a-b)^{2}+(a+b)^{2}}{a^{2}+b^{2}}=\frac{2\left(a^{2}+b^{2}\right)}{\left(a^{2}+b^{2}\right)}=2$.

Explanation as extracted from the printed page; notation may be imperfect.