ABC26GN0780 · Decimal Fractions

Subject: General Aptitude · Chapter: Decimal Fractions · Exam: 2010 · Marks: · Difficulty:

The value of $\left(\frac{0.125+0.027}{0.5 \times 0.5+0.09-0.15}\right)$ is
(a)0.08
(b)0.2
(c)0.8
(d)1
Answer
Answer (as printed): C
Explanation
Given expression $=\frac{(0.5)^{3}+(0.3)^{3}}{(0.5)^{2}+(0.3)^{2}-(0.5 \times 0.3)}$ $$\begin{aligned} & =\left(\frac{a^{3}+b^{3}}{a^{2}+b^{2}-a b}\right) \\ & =(a+b)=(0.5+0.3)=0.8 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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