If A+B=96 and A is half of B, then the value of A will be · ABC26GN0878

$A+B=96 \Rightarrow \frac{1}{2} B+B=96 \Rightarrow \frac{3}{2} B=96 \Rightarrow B=\left(96 \times \frac{2}{3}\right)=64$. $$\therefore \quad A=\left(\frac{1}{2} \times 64\right)=32 .$$