ABC26GN0891 · Simplification

Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:

If $a, b, c$, $\_\_\_\_$$x, y, z$ are 26 natural numbers, then the value of $$(x-a)(x-b)(x-c)$$ $\_\_\_\_$$(x-y)(x-z)$ is

(a)0

(b)1

(c)13

(d)26

Answer

Answer (as printed): A

Explanation

$(x-a)(x-b)(x-c) \ldots(x-y)(x-z)$ $=(x-a)(x-b)(x-c) \ldots(x-x)(x-y)(x-z)$ $=\{(x-a)(x-b)(x-c) \ldots(x-w)\} \times 0 \times[(x-y)(x-z)]$ $=0$.

Explanation as extracted from the printed page; notation may be imperfect.