ABC26GN0953 · Simplification

Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:

Let R = gS – 4, when S = 8 and R = 16. If S = 10, then R is equal to
(a)11
(b)14
(c)20
(d)21
Answer
Answer (as printed): D
Explanation
Putting S = 8 and R = 16, we have: $R = gS - 4 \Rightarrow 16 = 8g - 4 \Rightarrow 8g = 20 \Rightarrow g = \frac{20}{8} = \frac{5}{2}$. When S = 10, $R = gS - 4 \Rightarrow R = \frac{5}{2} \times 10 - 4 = 25 - 4 = 21$.

Explanation as extracted from the printed page; notation may be imperfect.

Open in whiteboard · Browse this chapter in the app