If a/(b+c)=b/(c+a)=c/(a+b)=K, then the value of K is · ABC26GN0979
Subject: General Aptitude · Chapter: Simplification
If $\frac{a}{b+c}=\frac{b}{c+a}=\frac{c}{a+b}=K$, then the value of $K$ is
(a)$\pm \frac{1}{2}$
(b)$\frac{1}{2}$ or - 1
(c)- 1
(d)$\frac{1}{2}$
Answer
Explanation
$$\begin{aligned} & \frac{a}{b+c}=K \Rightarrow a=K(b+c) \\ & \frac{b}{c+a}=K \Rightarrow b=K(c+a) \\ & \frac{c}{a+b}=K \Rightarrow c=K(a+b) \end{aligned}$$
Explanation as extracted from the printed page; notation may be imperfect.
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