ABC26GN1012 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: · Marks: · Difficulty:
$a$ is greater than $b$ by 2 and $b$ is greater than $c$ by 10. If $a+b+c=130$, then $(b+c)-a=$ ?
(a)34
(b)38
(c)42
(d)44
(e)None of these
Answer
Explanation
$a=b+2 \Rightarrow b=a-2$ And, $b=c+10 \Rightarrow c=b-10=(a-2)-10=a-12$. $$\begin{aligned} a+b+c=130 & \Rightarrow a+(a-2)+(a-12)=130 \\ & \Rightarrow 3 a=144 \Rightarrow a=48 \end{aligned}$$ $\therefore(b+c)-a=[(a-2)+(a-12)]-a$ $$=(2 a-14)-a=(a-14)=48-14=34 .$$
Explanation as extracted from the printed page; notation may be imperfect.
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