Water boils at 212°F or 100°C and melts at 32°F or 0°C. If the temperature of a particular day is 35°C, it is equivalent to
(a)85°F
(b)90°F
(c)95°F
(d)99°F
Answer
Answer (as printed): C
Explanation
Let F and C denote the temperatures in Fahrenheit and Celsius respectively. Then, $\frac{\mathrm{F}-32}{212-32}=\frac{\mathrm{C}-0}{100-0} \Leftrightarrow \frac{\mathrm{F}-32}{180}=\frac{\mathrm{C}}{100}$. If $\mathrm{C}=35$, then $\mathrm{F}=\left(\frac{35}{100} \times 180\right)+32=63+32=95$.