ABC26GN1046 · Simplification
Subject: General Aptitude · Chapter: Simplification · Exam: 2009 · Marks: · Difficulty:
If $3 y+9 x=54$ and $\frac{28 x}{13 y}=\frac{140}{39}$, then what is the value of $y-x$ ?
(a)- 2
(b)- 1
(c)1
(d)2
(e)None of these
Answer
Explanation
$$\begin{aligned} & \frac{28 x}{13 y}=\frac{140}{39} \Rightarrow \frac{x}{y}=\left(\frac{140}{39} \times \frac{13}{28}\right)=\frac{5}{3} \Rightarrow x=\frac{5}{3} y . \\ & \quad 3 y+9 x=54 \Rightarrow y+3 x=18 \\ & \quad \Rightarrow y+3 \times \frac{5}{3} y=18 \Rightarrow 6 y=18 \Rightarrow y=3 . \\ & \therefore \quad x=\left(\frac{5}{3} \times 3\right)=5 . \end{aligned}$$ So, $\quad y-x=(3-5)=-2$.
Explanation as extracted from the printed page; notation may be imperfect.
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