ABC26GN1070 · Simplification

Subject: General Aptitude · Chapter: Simplification · Exam: 2007 · Marks: · Difficulty:

When simplified, the product $\left(2-\frac{1}{3}\right)\left(2-\frac{3}{5}\right)$ $\left(2-\frac{5}{7}\right) \cdots\left(2-\frac{997}{999}\right)$ is equal to
(a)$\frac{5}{999}$
(b)$\frac{1001}{999}$
(c)$\frac{1}{1001}$
(d)$\frac{1001}{3}$
Answer
Answer (as printed): D
Explanation
Given exp. $=\frac{5}{3} \times \frac{7}{5} \times \frac{9}{7} \times \ldots . . \times \frac{1001}{999}=\frac{1001}{3}$.

Explanation as extracted from the printed page; notation may be imperfect.

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