If $a+b+c=0$, the value of $\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b}$ is
(a)3abc
(b)$\frac{1}{3}$
(c)1
(d)3
Answer
Answer (as printed): D
Explanation
$\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b}=\frac{a^{3}+b^{3}+c^{3}}{a b c}=\frac{3 a b c}{a b c}=3$. $\left[\because a+b+c=0 \Rightarrow a^{3}+b^{3}+c^{3}=3 a b c\right]$
Explanation as extracted from the printed page; notation may be imperfect.