ABC26GN1241 · Simplification

Subject: General Aptitude · Chapter: Simplification · Exam: 2009 · Marks: · Difficulty:

If each child is given 10 sweets, there are 3 sweets left over. But if each is given 11, then the number of sweets is 4 less. Find the number of sweets.
(a)37
(b)57
(c)73
(d)75
Answer
Answer (as printed): C
Explanation
Let the number of children be $x$. Then, $10 x+3=11 x-4$ $\Rightarrow x=7$. $\therefore \quad$ Number of sweets $=(10 \times 7+3)=73$.

Explanation as extracted from the printed page; notation may be imperfect.

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