Method: In the given number, mark off the digits in pairs starting from the unit's digit; each pair, and the remaining one digit, is called a period. Now, $1^2=1$; subtracting, the remainder is 0. Bring down the next period, 47. The trial divisor is $1 \times 2=2$ and the trial dividend is 47, so we take 22 as divisor and 2 as quotient; the remainder is 3. Bring down the next period, 13. The trial divisor is $12 \times 2=24$ and the trial dividend is 313, so we take 241 as divisor and 1 as quotient; the remainder is 72. Bring down the next period, 69. The trial divisor is $121 \times 2=242$ and the trial dividend is 7269, so we take 3 as quotient and 2423 as divisor; the remainder is then zero. Hence, $\sqrt{1471369}=1213$.
Explanation as extracted from the printed page; notation may be imperfect.