If √(x) ÷ √(441)=0.02, then the value of x is · ABC26GN1379

Subject: General Aptitude · Chapter: Square Roots and Cube Roots

If $\sqrt{x} \div \sqrt{441}=0.02$, then the value of $x$ is
(a)0.1764
(b)1.764
(c)1.64
(d)2.64
Answer
Answer (as printed): A
Explanation
$$\begin{aligned} & \frac{\sqrt{x}}{\sqrt{441}}=0.02 \Leftrightarrow \frac{\sqrt{x}}{21}=0.02 \\ & \begin{aligned} \Leftrightarrow \quad \sqrt{x}=0.02 \times 21 & =0.42 \Leftrightarrow x \\ & =(0.42)^{2}=0.1764 . \end{aligned} \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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