ABC26GN1388 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: · Marks: · Difficulty:

If $\sqrt{1+\frac{x}{169}}=\frac{14}{13}$, then $x$ is equal to
(a)1
(b)13
(c)27
(d)None of these
Answer
Answer (as printed): C
Explanation
$$\begin{aligned} & \sqrt{1+\frac{x}{169}}=\frac{14}{13} \Rightarrow 1+\frac{x}{169}=\frac{196}{169} \\ & \Rightarrow \frac{x}{169}=\left(\frac{196}{169}-1\right)=\frac{27}{169} \Rightarrow x=27 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

Open in whiteboard · Browse this chapter in the app