ABC26GN1392 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: · Marks: · Difficulty:

$(2 \sqrt{27}-\sqrt{75}+\sqrt{12})$ is equal to
(a)$\sqrt{3}$
(b)$2 \sqrt{3}$
(c)$3 \sqrt{3}$
(d)$4 \sqrt{3}$
Answer
Answer (as printed): C
Explanation
$$\begin{aligned} 2 \sqrt{27}-\sqrt{75}+\sqrt{12} & =2 \sqrt{9 \times 3}-\sqrt{25 \times 3}+\sqrt{4 \times 3} \\ & =6 \sqrt{3}-5 \sqrt{3}+2 \sqrt{3}=3 \sqrt{3} \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

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