ABC26GN1453 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: 2010 · Marks: · Difficulty:

$\frac{\sqrt{3+x}+\sqrt{3-x}}{\sqrt{3+x}-\sqrt{3-x}}=2$. Then $x$ is equal to
(a)$\frac{5}{7}$
(b)$\frac{7}{5}$
(c)$\frac{5}{12}$
(d)$\frac{12}{5}$
Answer
Answer (as printed): D
Explanation
No explanation was printed for this question.

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