99 × 21-3√(?)=1968 · ABC26GN1464

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: NABARD 2008

$99 \times 21-\sqrt[3]{?}=1968$
(a)1367631
(b)111
(c)1366731
(d)1367
Answer
Answer (as printed): A
Explanation
Let $99 \times 21-\sqrt[3]{x}=1968$. Then, $2079-\sqrt[3]{x}=1968 \Leftrightarrow \sqrt[3]{x}=2079-1968=111$ $$\Leftrightarrow x=(111)^{3}=1367631 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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