ABC26GN1464 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: 2008 · Marks: · Difficulty:

$99 \times 21-\sqrt[3]{?}=1968$

(a)1367631

(b)111

(c)1366731

(d)1367

Answer

Answer (as printed): A

Explanation

Let $99 \times 21-\sqrt[3]{x}=1968$. Then, $2079-\sqrt[3]{x}=1968 \Leftrightarrow \sqrt[3]{x}=2079-1968=111$ $$\Leftrightarrow x=(111)^{3}=1367631 .$$

Explanation as extracted from the printed page; notation may be imperfect.

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