ABC26GN1469 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: 2006 · Marks: · Difficulty:

Value of $\sqrt{.01} \times \sqrt[3]{.008}-.02$ is
(a)0
(b)1
(c)2
(d)3
Answer
Answer (as printed): A
Explanation
$$\begin{array}{r} \sqrt{.01} \times \sqrt[3]{.008}-.02=\sqrt{(.1)^{2}} \times \sqrt[3]{(.2)^{3}}-.02 \\ =.1 \times .2-.02=.02-.02=0 \end{array}$$

Explanation as extracted from the printed page; notation may be imperfect.

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