If √(7)=2.645, then the value of 1/(√(28)) up to three places of decimal is [SSC-CHSL (10+2) Exam, 2015] · ABC26GN1480

Subject: General Aptitude · Chapter: Square Roots and Cube Roots

If $\sqrt{7}=2.645$, then the value of $\frac{1}{\sqrt{28}}$ up to three places of decimal is [SSC-CHSL (10+2) Exam, 2015]
(a)0.183
(b)0.185
(c)0.187
(d)0.189
Answer
Answer (as printed): D
Explanation
$$\begin{aligned} & \frac{1}{\sqrt{28}}=\frac{1}{\sqrt{2 \times 2 \times 7}}=\frac{1}{2 \sqrt{7}} \\ & =\frac{\sqrt{7}}{2 \sqrt{7} \times \sqrt{7}}=\frac{\sqrt{7}}{14} \\ & =\frac{2.645}{14}=0.189 \end{aligned}$$

Explanation as extracted from the printed page; notation may be imperfect.

Study loop for Square Roots and Cube Roots

1. Practise the PYQsPrevious-year questions, with answers

· Browse this chapter in the app