ABC26GN1490 · Square Roots and Cube Roots

Subject: General Aptitude · Chapter: Square Roots and Cube Roots · Exam: · Marks: · Difficulty:

$\sqrt{?}+14=\sqrt{2601}$ [SBI Jr. Associates (Pre.) Exam, 2016]
(a)1521
(b)1369
(c)1225
(d)961
Answer
Answer (as printed): B
Explanation
Let the number be $x$. Given $\sqrt{x}+14=\sqrt{2601}$ $$\text { or, } \sqrt{x}=51-14=37$$ or $x=37^{2}=1369$

Explanation as extracted from the printed page; notation may be imperfect.

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