√(?)+14=√(2601) [SBI Jr. Associates (Pre.) Exam, 2016] · ABC26GN1490

Subject: General Aptitude · Chapter: Square Roots and Cube Roots

$\sqrt{?}+14=\sqrt{2601}$ [SBI Jr. Associates (Pre.) Exam, 2016]

(a)1521

(b)1369

(c)1225

(d)961

Answer

Answer (as printed): B

Explanation

Let the number be $x$. Given $\sqrt{x}+14=\sqrt{2601}$ $$\text { or, } \sqrt{x}=51-14=37$$ or $x=37^{2}=1369$

Explanation as extracted from the printed page; notation may be imperfect.

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