Subject: General Aptitude · Chapter: Average · Exam: · Marks: · Difficulty:
Find the average of first 40 natural numbers.
Answer
Answer (as printed):
Explanation
Sum of first $n$ natural numbers $=\frac{n(n+1)}{2}$. So, sum of first 40 natural numbers $=\frac{40 \times 41}{2}=820$. $$\text { ∴ Required average }=\frac{820}{40}=20.5 .$$
Explanation as extracted from the printed page; notation may be imperfect.