ABC26GN1503 · Average
Subject: General Aptitude · Chapter: Average · Exam: 2008 · Marks: · Difficulty:
The average of five consecutive numbers A, B, C, D and E is 48. What is the product of A and E?
Answer
Explanation
Let the numbers $A, B, C, D$ and $E$ be $x,(x+1),(x+2),(x+3)$ and $(x+4)$ respectively. Then, $$\frac{x+(x+1)+(x+2)+(x+3)+(x+4)}{5}=48 \Rightarrow 5 x+10=240 \Rightarrow 5 x=230 \Rightarrow x=46 .$$ So, $\mathrm{A}=x=46$ and $E=(x+4)=50$. $$\text { ∴ Required product }=46 \times 50=2300 .$$
Explanation as extracted from the printed page; notation may be imperfect.
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