Subject: General Aptitude · Chapter: Average · Exam: 2007 · Marks: · Difficulty:
10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child.
Answer
Answer (as printed):
Explanation
Total age of 4 members, 10 years ago = (24 × 4) years = 96 years. Total age of 4 members now = (96 + 10 × 4) years = 136 years. Total age of 6 members now = (24 × 6) years = 144 years. Sum of the ages of 2 children = (144 – 136) years = 8 years. Let the age of the younger child be x years. Then, age of the elder child = (x + 2) years. So, x + x + 2 = 8 ⇒ 2x = 6 ⇒ x = 3. \ Age of the younger child = 3 years.
Explanation as extracted from the printed page; notation may be imperfect.