The mean of the first ten even natural numbers is · ABC26GN1535

Required mean $=\left(\frac{2+4+6+\cdots+20}{10}\right)=\frac{2(1+2+\cdots+10)}{10}$ $$\begin{aligned} & =\left(\frac{1}{5} \times \frac{10 \times 11}{2}\right)=11 . \\ & \quad\left[\because 1+2+3+\cdots+n=\frac{n(n+1)}{2}\right] \end{aligned}$$