ABC26GN1539 · Average

Subject: General Aptitude · Chapter: Average · Exam: · Marks: · Difficulty:

The average of the first nine prime numbers is

(a)9

(b)11

(c)$11 \frac{1}{9}$

(d)$11 \frac{2}{9}$

Answer

Answer (as printed): C

Explanation

Average $=\left(\frac{2+3+5+7+11+13+17+19+23}{9}\right)$ $$=\frac{100}{9}=11 \frac{1}{9} .$$

Explanation as extracted from the printed page; notation may be imperfect.