Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 2010 · Marks: · Difficulty:
If the sum of two numbers is 42 and their product is 437, then find the absolute difference between the numbers.
Answer
Answer (as printed):
Explanation
Let the numbers be $x$ and $y$. Then, $x+y=42$ and $xy=437$. $x-y=\sqrt{(x+y)^{2}-4xy}=\sqrt{(42)^{2}-4\times437}=\sqrt{1764-1748}=\sqrt{16}=4$. Required difference $=4$.
Explanation as extracted from the printed page; notation may be imperfect.