If the sum of two numbers is 42 and their product is 437, then find the absolute difference between the… · ABC26GN1632
Subject: General Aptitude · Chapter: Problems on Numbers · Exam: S.S.C., 2003; B.Ed. 2010
If the sum of two numbers is 42 and their product is 437, then find the absolute difference between the numbers.
Answer
No answer key was printed for this question.
Explanation
Let the numbers be $x$ and $y$. Then, $x+y=42$ and $xy=437$. $x-y=\sqrt{(x+y)^{2}-4xy}=\sqrt{(42)^{2}-4\times437}=\sqrt{1764-1748}=\sqrt{16}=4$. Required difference $=4$.
Explanation as extracted from the printed page; notation may be imperfect.