Subject: General Aptitude · Chapter: Problems on Numbers · Exam: · Marks: · Difficulty:
50 is divided into two parts such that the sum of their reciprocals is $\frac{1}{12}$. Find the two parts.
Answer
Answer (as printed):
Explanation
Let the two parts be $x$ and $(50-x)$. Then, $\frac{1}{x}+\frac{1}{50-x}=\frac{1}{12} \Rightarrow \frac{50-x+x}{x(50-x)}=\frac{1}{12} \Rightarrow x^{2}-50x+600=0 \Rightarrow (x-30)(x-20)=0 \Rightarrow x=30 \text{ or } x=20$. So, the parts are 30 and 20.
Explanation as extracted from the printed page; notation may be imperfect.