ABC26GN1675 · Problems on Numbers

Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 2007 · Marks: · Difficulty:

The sum and product of two numbers are 12 and 35 respectively. The sum of their reciprocals will be

(a)$\frac{12}{35}$

(b)$\frac{1}{35}$

(c)$\frac{35}{8}$

(d)$\frac{7}{32}$

Answer

Answer (as printed): A

Explanation

Let the numbers be $x$ and $y$. Then, $x+y=12$ and $x y=35$. $$\therefore \quad \frac{1}{x}+\frac{1}{y}=\frac{x+y}{x y}=\frac{12}{35} .$$

Explanation as extracted from the printed page; notation may be imperfect.