Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 2010 · Marks: · Difficulty:
Out of six consecutive natural numbers if the sum of first three is 27, what is the sum of the other three?
(a)24
(b)25
(c)35
(d)36
Answer
Answer (as printed): D
Explanation
Let the six numbers be $x, x+1, x+2, x+3, x+4$ and $x+5$. Then, $x+(x+1)+(x+2)=27 \Rightarrow 3 x+3=27$. Required sum $=(x+3)+(x+4)+(x+5)$ $$=3 x+12=(3 x+3)+9=27+9=36 .$$
Explanation as extracted from the printed page; notation may be imperfect.