ABC26GN1718 · Problems on Numbers

Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 1998 · Marks: · Difficulty:

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is

(a)9

(b)11

(c)13

(d)15

Answer

Answer (as printed): D

Explanation

Let the three integers be $x, x+2$ and $x+4$. Then, $3 x=2(x+4)+3 \Leftrightarrow x=11$. $\therefore \quad$ Third integer $=x+4=15$.

Explanation as extracted from the printed page; notation may be imperfect.