ABC26GN1725 · Problems on Numbers

Subject: General Aptitude · Chapter: Problems on Numbers · Exam: 2006 · Marks: · Difficulty:

If the product of three consecutive integers is 120, then the sum of the integers is

(a)9

(b)12

(c)14

(d)15

(e)18

Answer

Answer (as printed): D

Explanation

$120=2 \times 2 \times 2 \times 3 \times 5=(2 \times 2) \times 5 \times(2 \times 3)=4 \times 5 \times 6$. Clearly, the three consecutive integers whose product is 120 are 4, 5 and 6. Required sum $=4+5+6=15$.

Explanation as extracted from the printed page; notation may be imperfect.

Open in whiteboard · Browse this chapter in the app